Geometry • Conic Sections Flagship

Hyperbola Calculator

Solve horizontal and vertical hyperbolas for standard form, center $(h, k)$, transverse axis ($a$), conjugate axis ($b$), linear asymptotes, foci coordinates, and eccentricity ($e > 1$) with interactive SVG plots.

Verified Hyperbolic Asymptotic & LORAN Proofs
Last Updated: September 2026
Presets:
Circle Standard Equation Solution
(x - 0)² + (y - 0)² = 25
Center (h, k) Point
(0, 0)
Symmetry Origin
Radius (r) Length
5
Diameter d = 10
Eccentricity (e) Ratio
0
Perfect Circle (e = 0)
Enclosed Area Metric
78.54
25π square units
General Quadratic Form: x² + y² - 25 = 0

Conic Cartesian Coordinate Plot

Scale: Auto-Fitting
Center / Vertex
Foci Points (F₁, F₂)
Asymptotes / Directrix

Geometric Properties

Exact Dimensions
Axis of Symmetry All Lines through (0,0)
X-Intercepts (-5, 0), (5, 0)
Y-Intercepts (0, -5), (0, 5)
Focal Parameter (c) c = 0
Asymptotes / Directrix None
Direct Answer & Overview
Verified Educational Guide

Hyperbola Definition & Standard Formulas

A hyperbola is the open conic section with eccentricity e > 1, defined as the locus of points where the absolute difference in distances to two foci is constant (2a). Its open branches are bounded by two linear asymptotes passing through the center.

Primary Mathematical Formula Standard Mathematical Model
Standard Equation
ƒ(x)
Q.E.D.
Horizontal: (x − h)²/a² − (y − k)²/b² = 1, Asymptotes: y − k = ±(b/a)(x − h), Focal Distance: c = √(a² + b²), Eccentricity: e = c/a > 1
Evaluated with exact mathematical formulation • Rigorously verified
Exact Formula
Input Parameters
Required
1
Center coordinates (h, k)
2
Transverse semi-axis (a)
3
Conjugate semi-axis (b)
4
Transverse axis orientation (Horizontal opening left/right or Vertical opening up/down)
Expected Outputs
Calculated
Standard Form Equation
Linear Asymptotes Equations: y - k = ±m(x - h)
Foci Coordinates (F₁, F₂)
Eccentricity Value (e > 1)
Interactive SVG coordinate canvas plot
Worked Numerical Example
Instant Verification
Find asymptotes, foci, and eccentricity for hyperbola (x - 0)²/16 - (y - 0)²/9 = 1
→ a = 4, b = 3. Focal distance c = √(16 + 9) = √25 = 5. Eccentricity e = 5/4 = 1.25. Asymptote slopes m = ±3/4.
Asymptotes: y = ±0.75x, Foci = (±5, 0), e = 1.25

Hyperbola Conic Definition & Two-Foci Distance Difference Locus

A hyperbola is the geometric locus of all points $P(x, y)$ in a plane such that the absolute difference of its distances from two fixed points $F_1$ and $F_2$ (the foci) is constant and equal to the transverse axis length $2a$:

$$|d(P, F_1) - d(P, F_2)| = 2a \quad (a > 0, b > 0)$$

The line segment of length $2a$ connecting the vertices through the center and foci is the transverse axis. The perpendicular line segment of length $2b$ through the center is the conjugate axis.

Standard Form Equations (Horizontal vs Vertical Transverse Axis)

Horizontal Hyperbola (Opens Left / Right)
$\frac{(x - h)^2}{a^2} - \frac{(y - k)^2}{b^2} = 1$
  • Transverse axis is horizontal ($y = k$).
  • Vertices: $(h \pm a, k)$
  • Foci: $(h \pm c, k)$ where $c = \sqrt{a^2 + b^2}$
  • Asymptotes: $y - k = \pm \frac{b}{a}(x - h)$
Vertical Hyperbola (Opens Up / Down)
$\frac{(y - k)^2}{a^2} - \frac{(x - h)^2}{b^2} = 1$
  • Transverse axis is vertical ($x = h$).
  • Vertices: $(h, k \pm a)$
  • Foci: $(h, k \pm c)$ where $c = \sqrt{a^2 + b^2}$
  • Asymptotes: $y - k = \pm \frac{a}{b}(x - h)$

Linear Asymptotes Equations & Central Rectangle Geometry

The asymptotes of a hyperbola act as guiding linear boundaries that the curve approaches infinitely closely as $|x| \to \infty$. They are found by replacing the right-hand constant 1 with 0:

$$\frac{(x - h)^2}{a^2} - \frac{(y - k)^2}{b^2} = 0 \implies \frac{y - k}{b} = \pm \frac{x - h}{a} \implies y - k = \pm \frac{b}{a}(x - h)$$

Geometrically, the asymptotes pass through the diagonals of the central bounding rectangle of width $2a$ and height $2b$ centered at $(h, k)$.

Focal Parameter ($c = \sqrt{a^2 + b^2}$) & Eccentricity ($e > 1$)

Focal Parameter ($c$)
$$c = \sqrt{a^2 + b^2}$$

For a hyperbola, $c > a$ always, meaning the foci lie further from the center than the vertices.

Eccentricity ($e$)
$$e = \frac{c}{a} = \sqrt{1 + \frac{b^2}{a^2}} > 1$$

Measures the openness of the hyperbolic branches. Larger $e$ produces wider asymptote angles.

Real-World Applications (LORAN Navigation & Gravitational Slingshots)

LORAN Radio Navigation

Coastal navigation receivers measure constant arrival time differences $\Delta t$ between transmitter pairs ($F_1, F_2$), tracing hyperbolic position lines on marine charts.

Gravitational Slingshots

Spacecraft (like Voyager 1 & 2) performing planetary flybys exceed escape velocity, traveling on open hyperbolic trajectories ($e > 1$) relative to the planet.

Nuclear Cooling Towers

Hyperboloid structural profiles minimize concrete volume while maximizing upward draft airflow and structural rigidity against high crosswinds.

Graded Step-by-Step Numerical Solutions

Example 1 • Horizontal Hyperbola Analysis Standard Tier

Analyze the hyperbola $\frac{(x - 1)^2}{9} - \frac{(y + 2)^2}{16} = 1$.

1. Center $(h, k) = (1, -2)$.

2. Positive term is $x$, so transverse axis is horizontal ($y = -2$). $a^2 = 9 \implies a = 3$, $b^2 = 16 \implies b = 4$.

3. Vertices: $(1 \pm 3, -2) \implies (4, -2)$ and $(-2, -2)$.

4. Focal distance $c = \sqrt{9 + 16} = \sqrt{25} = 5$. Foci: $(1 \pm 5, -2) \implies F_1(6, -2), F_2(-4, -2)$.

5. Asymptotes: $y - (-2) = \pm \frac{4}{3}(x - 1) \implies y + 2 = \pm \frac{4}{3}(x - 1)$.

Eccentricity $e = 5/3 \approx 1.667$.

Common Pitfalls & Minus Sign Orientation Rules

Pitfall 1: Relying on Size of Denominator to Determine Orientation
Unlike an ellipse (where $a > b$ always), in a hyperbola $a$ is whichever variable has the positive coefficient. Even if $b > a$ (e.g. $\frac{x^2}{4} - \frac{y^2}{25} = 1$), the hyperbola is still horizontal because the $x^2$ term is positive.
Pitfall 2: Inverting Asymptote Slopes for Vertical Hyperbolas
For a horizontal hyperbola, asymptote slope is $\pm \frac{b}{a}$. For a vertical hyperbola $\frac{y^2}{a^2} - \frac{x^2}{b^2} = 1$, the slope is $\pm \frac{a}{b} = \pm \frac{\Delta y}{\Delta x}$. Always ensure $\Delta y$ is in the numerator.
Fact-Checked & Verified • Computational Accuracy Standards
Updated July 2026 • Editorial Policy
Authored By
Sanjay Samanta

Lead Developer & Founder of Basic Math Tools. Specializes in browser-native computational algorithms and applied mathematics.

Reviewed & Verified By
Academic Review Board

Mathematics & curriculum specialists. Audited against standard algebraic and arithmetic principles.

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Frequently Asked Questions

What is the standard equation of a hyperbola?
For a horizontal hyperbola (opening left/right), the standard form is (x − h)²/a² − (y − k)²/b² = 1. For a vertical hyperbola (opening up/down), the standard form is (y − k)²/a² − (x − h)²/b² = 1, where (h, k) is the center.
What is the geometric locus definition of a hyperbola?
A hyperbola is the set of all points P in a plane such that the absolute difference of the distances from P to two fixed foci F₁ and F₂ is strictly constant: |d(P, F₁) − d(P, F₂)| = 2a (where 2a is the transverse axis length).
How do you find the linear asymptotes of a hyperbola?
For a horizontal hyperbola, the asymptotes are y − k = ±(b/a)(x − h). For a vertical hyperbola, the asymptotes are y − k = ±(a/b)(x − h). They represent the diagonal lines that the hyperbola branches approach as x and y tend to infinity.
How do you calculate focal distance c and eccentricity e for a hyperbola?
The focal distance from the center to each focus is c = √(a² + b²). The eccentricity is e = c / a. For all hyperbolas, e > 1.
How are hyperbolas used in LORAN navigation and orbital mechanics?
In radio navigation (LORAN/GPS), synchronized radio signals received with a constant time difference locate the ship along a hyperbolic position curve. In orbital mechanics, celestial bodies with velocities exceeding escape velocity travel on open hyperbolic escape trajectories around a gravitational body.